一、真实环境

第一步：concat_ws()，把需要的四列合并成以逗号隔开的字符串，形成新的列corpName

SELECT L_PARK,RC_PM_UIDS ,RC_MC_UIDS,RC_MC_ADMIN,RC_PM_ADMIN,
group_concat(distinct(concat_ws(',',RC_PM_ADMIN,RC_MC_ADMIN,RC_PM_UIDS,RC_MC_UIDS))) corpName FROM dev_lift WHERE 1=1 and id in (select id from dev_lift where STATUS>0 and L_AREA=523) group by L_PARK

 需求：现在要实现的结果就是把哪些id替换成对应人物的公司名，展示如下：

第二步：怎么实现

1.新建一个test_topic(随便取)表，添加死数据。从0开始 

2.使用 SUBSTRING_INDEX函数跟test_topic表连接，语句如下

例子

 SELECT SUBSTRING_INDEX(SUBSTRING_INDEX('1,3,21,5,9',',',topic_id+1),',',-1) AS num FROM test_topic WHERE topic_id < LENGTH('1,3,21,5,9')-LENGTH(REPLACE('1,3,21,5,9',',',''))+1

 然后你把刚才那个语句套在你的 In()条件里就可以了，同时查询条件加

group_concat() 函数。

SELECT group_concat(name) from auth a left join corp c on a.corp=c.id where a.id in ( 
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(corpName,',',topic_id+1),',',-1) AS num FROM corp_topic WHERE topic_id < LENGTH(corpName)-LENGTH(REPLACE(corpName,',',''))+1 )

由于我的数据有重复,需要去重分组等一些操作。

完整sql。你能套就套

SELECT L_PARK parkId, weibao,anbao,weibaojinli,wuyejinli, 
(SELECT group_concat( DISTINCT c.name ) from auth a left join corp c on a.corp=c.id                     
where a.id in ( 
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(corpName,',',topic_id+1),',',-1) AS num FROM     
corp_topic 
WHERE topic_id < LENGTH(corpName)-LENGTH(REPLACE(corpName,',',''))+1 )) corpName 

FROM ( 
    SELECT L_PARK,group_concat(distinct(RC_PM_UIDS))     
    anbao,group_concat(distinct(RC_MC_UIDS)) weibao, 
    group_concat(distinct(RC_MC_ADMIN)) weibaojinli,group_concat(distinct(RC_PM_ADMIN))     
    wuyejinli, 
    group_concat(distinct(concat_ws(',',RC_PM_ADMIN,RC_MC_ADMIN,RC_PM_UIDS,RC_MC_UIDS))) 
    corpName 
    FROM dev_lift 
    group by L_PARK  
)c