oracle实战之ORA-00907: 缺失右括号
ORA-00907 缺失右括号,右括号缺失问题
·
SELECT ref.id, com.code,
IF(
ref.check_state=1,
(SELECT sc.content FROM str_com_save_content sc WHERE sc.ref_id=ref.id ORDER BY sc.id DESC LIMIT 1),
com.content
) content,
CASE
WHEN (SELECT COUNT(1) FROM str_com_reference cr WHERE cr.strategy_id=ref.strategy_id AND cr.component_id=ref.component_id) > 0 THEN 0
ELSE 1
END AS use_state
FROM str_component_ref ref
LEFT JOIN str_directory dir ON ref.directory_id=dir.id,
str_component com
sql做了简化,只描述具体问题
-
报错原因分析:
在子句中使用了order by,会导致缺失右括号的错误 -
解决方案:
使用join on的方式,将子句拆分。然后用case替换if函数。然后limit 1使用row_number() OVER(PARTITION BY * ORDER BY * ) 替换
SELECT ref.id, com.code,
CASE
WHEN ref.check_state=1 THEN scr.CONTENT
ELSE com.CONTENT
END AS content,
CASE
WHEN (SELECT COUNT(1) FROM str_com_reference cr WHERE cr.strategy_id=ref.strategy_id AND
cr.component_id=ref.component_id) > 0 THEN 0
ELSE 1
END AS use_state
FROM str_component_ref ref
LEFT JOIN (SELECT ROW_NUMBER() OVER(PARTITION BY REF_ID ORDER BY ID DESC) rn, sc.* FROM STR_COM_SAVE_CONTENT sc) scr ON scr.rn=1 and scr.ref_id=ref.id
LEFT JOIN str_directory dir ON ref.directory_id=dir.id,
str_component com

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