嵌入式学习第二十八天!(数据库)
1. 关系型数据库:Mysql、Oracle、SqlServer、2. 非关系型数据库:Redis、NoSQL。
数据库:
1. 数据库软件:
1. 关系型数据库:Mysql、Oracle、SqlServer、Sqlite
2. 非关系型数据库:Redis、NoSQL
2. 数组、链表、文件、数据库
数组、链表:内存存放数据的方式(代码运行结束、关机数据丢失)
文件、数据库:外存存放数据的方式(代码运行结束、关机数据不会丢失)
文件:数据量很小,处理效率很低
数据库:数据量很大,处理数据(增删改查)效率高
3. 安装Sqlite数据库:
1. 让虚拟机能够哦上网
2. apt-get工具集配置好
3. sudo apt-get install sqlite3
4. 启动sqlite3
sqlite3
5. 输入.quit退出
4. SQL命令:
1. 打开/关闭 数据库中列名称
.headers on/off
2. 设置输出模式,MODE可以是csv逗号分隔的值、column左对齐的列等
.mode csv/column/html/insert/line/list/tabs/tcl
3. 查看表名对应的表的形式(有哪几列?每一列类型?)
.schema 表名称
4. 设置显示时的数据宽带
.width 宽度
5. 查看数据库文件中的所有表
.tables
这里只展示了几个常用的命令,其他命令可以查看SQLite参考手册中的SQLite命令
5. SQL语言:
数据的:增、删、改、查
1. 使用sqlite3打开数据库文件
sqlite3 数据库文件名
eg:
sqlite3 ./student.db
2. 创建/删除表:
create table 表名
eg:
sqlite> create table student (id integer primary key asc, name varchar(255), sex varchar(32), age integer, score integer);
drop table 表名
eg:
sqlite> drop table student
3. 插入数据:
insert into
eg:
sqlite> insert into student values (1001, "张三", "男", 19, 80);
sqlite> insert into student (id, name, score) values (1002, "李四", 100);
sqlite> insert into student values (1002, "王二", "女", 18, NULL);
4. 查找数据:
select
eg:
sqlite> select * from student;
sqlite> select name, score from student;
5. 内容匹配:
where
eg:
sqlite> select * from student where name like "%张%";
练习:数据库完成对订单的管理:
1. 创建一张订单表,由 ID, 订单号, 货物信息, 生产厂商, 联系人, 联系电话, 订单时间
sqlite> create table older_manage
...> (ID integer,
...> ordername varchar(32),
...> orderinfo varchar(50),
...> factoryname varchar(50),
...> contactperson varchar(32),
...> contactphone varchar(32),
...> oldertime varchar(32));
2. 在表中插入随机给定的10条数据
sqlite> insert into older_manage values(1, "D202403120001", "Mate60 手机", "华为", "张三", "19829147641", "20240312 22:04:00");
sqlite> insert into older_manage values(2, "D202403120002", "Mate 平板", "华为", "张三", "13819724571", "20240312 18:34:10");
sqlite> insert into older_manage values(3, "D202403120003", "GTWatch 手表", "华为", "张三", "13947231554", "20240312 10:14:15");
sqlite> insert into older_manage values(4, "D202403120004", "Iphone14 手机", "苹果", "李四", "13145721214", "20240311 12:31:42");
sqlite> insert into older_manage values(5, "D202403120005", "Ipad 平板", "苹果", "李四", "13147561243", "20240311 13:13:12");
sqlite> insert into older_manage values(6, "D202403120006", "Iwatch 手表", "苹果", "李四", "13147561478", "20240310 11:13:12");
...
3. 查找 联系人为 "张三" 的所有订单号
select ordername from older_manage where contactperson="张三";
查找 订单号为 "D202403120001" 的所有订单信息
select * from older_manage where oldername="D202403120001";
查找 订单时间截止到当天的所有订单号及联系人、联系电话
select oldername,contactperson,contactphone from older_manage where oldertime<"20240311 24:00:00";
查找 货物信息包含 "手机" 内容的所有订单信息及货物信息
select oldername,olderinfo from older_manage where olderinfo like "%手机%";
查找 生产厂商是"华为" 的所有货物信息包含 "平板" 的订单信息
select * from order_manage where factoryname="华为" and orderinfo like "%d平板%";
6. 主键:
key:键值
內键:在表中唯一标识一条数据称为內键
外键:与外部表进行标识的数据称为外键
7. 删除:
delete from
eg:
delete from student where name="李四";
8. 修改:
update
eg:
update student set sex="男", age="19" where name "王二";
9. 排序:
older by
eg:
select * from order_manage order by ordertime desc;
10. 多表联合查询:
1. 交叉连接:
cross join
eg:
sqlite> select student.name as 学生姓名, lesson.name as 课程名
...> from score cross join lesson;
2. 内连接:
inner join
eg:
sqlite> select score.id as 成绩编号, student.name as 学生姓名, score.score as 成绩
...> from score inner join student on score.stuid=student.id;
3. 外连接:
outer join
eg:
sqlite> select score.id as 成绩编号, student.name as 学生姓名, score.score as 成绩
...> from student left outer join score on score.stuid=stdent.id;
示例:
sqlite> select score.id as 成绩编号, student.name as 学生姓名, score.score as 成绩
...> from student left outer join score on score.stuid=student.id
...> where name="张三"
...> order by 成绩 desc;
6. 在程序中使用Sqlite3
可以寻找Sqlite3官网SQLite Home Page,主页选择Documentation,再选择Programming Interfaces中C/C++ API Reference去寻找Sqlite3数据库使用的函数接口,在调用时需要加上<sqlite3.h>,在这里讲解一些常用的函数接口:

1. sqlite3_open:
int sqlite3_open(
const char *filename, /* Database filename (UTF-8) */
sqlite3 **ppDb /* OUT: SQLite db handle */
);
功能:打开数据库文件(创建一个数据库连接)
参数:
failname:数据库文件路径
ppDb:操作数据库指针存放空间的首地址
返回值:
成功返回SQLITE_OK
失败返回错误码
2. sqlite3_close:
int sqlite3_close(sqlite3*);
功能:关闭数据库连接
3. sqlite3_exec
int sqlite3_exec(
sqlite3*, /* An open database */
const char *sql, /* SQL to be evaluated */
int (*callback)(void*,int,char**,char**), /* Callback function */
void *, /* 1st argument to callback */
char **errmsg /* Error msg written here */
);
功能:执行一条SQL语句
参数:
sqlite3*:数据库句柄
sql:要执行的SQL语句字符串首地址
callback:只有在select时才会使用,其余调用时传递NULL
void*:给回调函数的传参
errmsg:出错信息存放空间首地址(使用sqlite3_free释放空间)
返回值:
成功返回SQLITE_OK
失败返回错误码
练习:
1. 从终端输入一个单词,在文件中查找单词含义并打印在终端:
#include <stdio.h>
#include <string.h>
int main(void)
{
FILE * fd = NULL;
char str[64] = {0};
char tmpbuff[1024] = {0};
char *pread = NULL;
char *pstr = NULL;
fd = fopen("dict.txt", "r");
if(fd == NULL)
{
perror("fail to fopen");
return -1;
}
while(1)
{
gets(str);
if(!strcmp(str, ".quit"))
{
break;
}
while(1)
{
pread = fgets(tmpbuff, sizeof(tmpbuff), fd);
if(pread == NULL)
{
perror("fail to fgets");
rewind(fd);
break;
}
pstr = pread;
while(*pread != ' ' && *pread != '\0')
{
pread++;
}
*pread = '\0';
pread++;
if(!strcmp(str, pstr))
{
while(*pread == ' ')
{
pread++;
}
printf("%s\n", pread);
rewind(fd);
break;
}
}
}
fclose(fd);
return 0;
}

2. 实现将dict.txt文件中的所有单词和含义插入到数据库中,并实现单词的查找
#include "head.h"
#include <sqlite3.h>
int LoadDictToDB(void)
{
int ret = 0;
int eret = 0;
FILE *fp = NULL;
char *pstr = NULL;
char *pword = NULL;
char *pmean = NULL;
char tmpbuff[4096] = {0};
char cmpbuff[1024] = {0};
sqlite3 *pdb;
char *perrmsg;
fp = fopen("dict.txt", "r");
if(fp == NULL)
{
perror("fail to fopen");
return -1;
}
ret = sqlite3_open("dictionary.db", &pdb);
if(ret != SQLITE_OK)
{
fprintf(stderr, "sqlite3_open failed:%s\n", sqlite3_errmsg(pdb));
return -1;
}
sprintf(cmpbuff, "create table if not exists dict (id integer primary key asc, word varchar(50), mean varchar(1024));");
eret = sqlite3_exec(pdb, cmpbuff, NULL, NULL, &perrmsg);
if(eret !=SQLITE_OK)
{
fprintf(stderr, "sqlite3_exec failed:%s\n", perrmsg);
sqlite3_free(perrmsg);
sqlite3_close(pdb);
return -1;
}
while(1)
{
memset(tmpbuff, 0, sizeof(tmpbuff));
pword = fgets(tmpbuff, sizeof(tmpbuff), fp);
if(pword == NULL)
{
break;
}
pstr = tmpbuff;
while(*pstr != ' ')
{
pstr++;
}
*pstr = '\0';
pstr++;
while(*pstr == ' ')
{
pstr++;
}
pmean = pstr;
while(*pstr != '\r')
{
pstr++;
}
*pstr = '\0';
memset(cmpbuff, 0, sizeof(cmpbuff));
sprintf(cmpbuff, "insert into dict values(NULL, \"%s\", \"%s\");", pword, pmean);
eret = sqlite3_exec(pdb, cmpbuff, NULL, NULL, &perrmsg);
if(eret != SQLITE_OK)
{
printf("%s\n", cmpbuff);
fprintf(stderr, "sqlite3_exec failed:%s\n", perrmsg);
sqlite3_free(perrmsg);
sqlite3_close(pdb);
return -1;
}
}
fclose(fp);
sqlite3_close(pdb);
return 0;
}
int callback(void *arg, int col, char **pcontent, char **ptitle)
{
printf("%s: %s\n", ptitle[1], pcontent[2] );
return 0;
}
int main(void)
{
sqlite3 *pdb;
int ret = 0;
char str[256] = {0};
char cmpbuff[1024] = {0};
char *perrmsg = NULL;
if(access("dictionary.db", F_OK))
{
LoadDictToDB();
}
gets(str);
ret = sqlite3_open("dictionary.db", &pdb);
if(ret != SQLITE_OK)
{
fprintf(stderr, "sqlite3_open failed:%s\n", sqlite3_errmsg(pdb));
return -1;
}
sprintf(cmpbuff, "select * from dict where word = \"%s\";", str);
ret = sqlite3_exec(pdb, cmpbuff, callback, NULL, &perrmsg);
if(ret != SQLITE_OK)
{
fprintf(stderr, "sqlite3_exec failed:%s\n", perrmsg);
sqlite3_free(perrmsg);
sqlite3_close(pdb);
return -1;
}
sqlite3_close(pdb);
return 0;
}


3. 1037 在霍格沃茨找零钱 - PAT (Basic Level) Practice (中文) (pintia.cn)

#include <stdio.h>
struct money
{
int Galleon;
int Sickle;
int Knut;
};
void IntMoneyInfo(struct money *pay)
{
scanf("%d.%d.%d", &pay->Galleon, &pay->Sickle, &pay->Knut);
return;
}
void CountMoney(struct money pmax, struct money pmin, int *galleon, int *sickle, int *knut)
{
*knut = pmax.Knut - pmin.Knut;
if(*knut < 0)
{
pmax.Sickle -= 1;
*knut = (pmax.Knut + 29) - pmin.Knut;
}
*sickle = pmax.Sickle - pmin.Sickle;
if(*sickle < 0)
{
pmax.Galleon -= 1;
*sickle = (pmax.Sickle + 17) - pmin.Sickle;
}
*galleon = pmax.Galleon - pmin.Galleon;
return;
}
int main(void)
{
int galleon = 0;
int sickle = 0;
int knut = 0;
struct money accountspay;
struct money actualpay;
IntMoneyInfo(&accountspay);
IntMoneyInfo(&actualpay);
if(actualpay.Galleon > accountspay.Galleon)
{
CountMoney(actualpay, accountspay, &galleon, &sickle, &knut);
printf("%d.%d.%d\n", galleon, sickle, knut);
}
else
{
CountMoney(accountspay, actualpay, &galleon, &sickle, &knut);
printf("-%d.%d.%d\n", galleon, sickle, knut);
}
return 0;
}

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