OpenPose C++实现多人姿态估计

smoothProbMap.mul 执行了什么操作？

flyfish

cv::minMaxLoc(smoothProbMap.mul(blobMask),0,&maxVal,0,&maxLoc);

解释
MatExpr cv::Mat::mul ( InputArray m,double scale = 1) const

Performs an element-wise multiplication or division of the two matrices.
The method returns a temporary object encoding per-element array multiplication, with optional scale.
Note that this is not a matrix multiplication that corresponds to a simpler “*” operator.

执行两个矩阵的逐元素乘法或除法。
该方法返回编码每个元素数组乘法的临时对象，具有可选的小数位数位数。请注意，这不是与更简单的“*”运算符相对应的矩阵乘法。

假设有两个矩阵
$$A=\left[\begin{array}{ll}{a}_{00}& a_{01}\\ a_{10}& a_{11}\end{array}\right]B=\left[\begin{array}{ll}{b}_{00}& b_{01}\\ b_{10}& b_{11}\end{array}\right]$$

执行cv::Mat::mul的过程就是
$$A\cdot \mathrm{mul}(B)=\left[\begin{array}{ll}{a}_{00}\times b_{00}& a_{01}\times b_{01}\\ a_{10}\times b_{10}& a_{11}\times b_{11}\end{array}\right]$$
不是矩阵乘法
这里的A就是smoothProbMap，B就是blobMask