如果根据文件名或者创建人名进行模糊查询 

这种写法是错误的，容易导致查询条件逻辑混乱

List<KnowledgeBase> list = lambdaQuery()
                .eq(KnowledgeBase::getResourceType, 2)
                 .in(query.getRootIdIn().size()>0,KnowledgeBase::getRootId, query.getRootIdIn())
                 .like(KnowledgeBase::getResourceName, query.getResourceNameLike())
                 .or()
                 .like(KnowledgeBase::getCreateByName, query.getResourceNameLike()
                .orderByDesc(KnowledgeBase::getCreateTime)
                 .last("LIMIT 100")
                .list();

 应该吧这个or的放到一个and中

List<KnowledgeBase> list = lambdaQuery()
                .eq(KnowledgeBase::getResourceType, 2)
                 .in(query.getRootIdIn().size()>0,KnowledgeBase::getRootId, query.getRootIdIn())
                 .and(query.getResourceNameLike()!=null &&!("").equals(query.getResourceNameLike()),wrapper ->
                         wrapper.like(KnowledgeBase::getResourceName, query.getResourceNameLike())
                                 .or()
                                 .like(KnowledgeBase::getCreateByName, query.getResourceNameLike())
                 )
                .orderByDesc(KnowledgeBase::getCreateTime)
                 .last("LIMIT 100")
                .list();