# 取最值
pairs = {('s', 't</w>'): 9, ('e', 's'): 9, ('o', 'w</w>'): 5, ('l', 'o'): 7, ('w', 'e'): 8, ('o', 'w'): 2}
best = max(pairs, key=lambda x: (pairs[x], x))
print(best)

# 按照多个key排序，先按照字典的value排序，再按照字典key的字母顺序排序
pairs = {('s', 't</w>'): 9, ('e', 's'): 9, ('o', 'w</w>'): 5, ('l', 'o'): 7, ('w', 'e'): 8, ('o', 'w'): 2}
sorted_pairs = sorted(pairs, key=lambda x: (pairs[x], x), reverse=True)
print(sorted_pairs)

结果：

('s', 't</w>')
[('s', 't</w>'), ('e', 's'), ('w', 'e'), ('l', 'o'), ('o', 'w</w>'), ('o', 'w')]