matlab中nlinfit的意思,MATLABnlinfit秩亏
>> t=0:30;>> x=[107.507 109.300 111.026 112.704 114.333 115.823 117.171 118.517 119.850 121.121 122.389 123.626 124.761 125.786 126.743 127.627 128.453 129.227 129.988 130.756 131.448 132.
>> t=0:30;
>> x=[107.507 109.300 111.026 112.704 114.333 115.823 117.171 118.517 119.850 121.121 122.389 123.626 124.761 125.786 126.743 127.627 128.453 129.227 129.988 130.756 131.448 132.129 132.802 133.450 134.091 134.735 135.404 136.072 136.782 137.462 138.271];
>> syms c d
>> [c,d]=solve(c/(1+(c/107.507-1)*exp(-5*d))==115.823,c/(1+(c/107.507-1)*exp(-8*d))==119.850,c,d);
>> c=double(c)
c =
109.738281373644 - 1.60177395988749i
>> d=double(d)
d =
-0.150875720473954 - 2.06096070058854i
>> b0=[c,d];
>> [b,r,j]=nlinfit(t,x,fun,b0);
警告: 秩亏,秩 = 1,tol = 5.675835e-13。
> In nlinfit>LMfit (line 587)
In nlinfit (line 284)
警告: 秩亏,秩 = 1,tol = 4.209312e-13。
> In nlinfit>LMfit (line 587)
In nlinfit (line 284)
警告: 秩亏,秩 = 1,tol = 4.033439e-13。
> In nlinfit>LMfit (line 587)
In nlinfit (line 284)
警告: 秩亏,秩 = 1,tol = 4.015428e-13。
> In nlinfit>LMfit (line 587)
In nlinfit (line 284)
警告: Some columns of the Jacobian are effectively zero at the solution, indicating that the
model is insensitive to some of its parameters. That may be because those parameters are not
present in the model, or otherwise do not affect the predicted values. It may also be due to
numerical underflow in the model function, which can sometimes be avoided by choosing better
initial parameter values, or by rescaling or recentering. Parameter estimates may be
unreliable.
> In nlinfit (line 381)
>>
魔乐社区(Modelers.cn) 是一个中立、公益的人工智能社区,提供人工智能工具、模型、数据的托管、展示与应用协同服务,为人工智能开发及爱好者搭建开放的学习交流平台。社区通过理事会方式运作,由全产业链共同建设、共同运营、共同享有,推动国产AI生态繁荣发展。
更多推荐


所有评论(0)