jqgrid ajax加载数据,如何通过ajax在jqgrid中加载数据(json)?
我有一个函数(在Java小服务程序)返回该JSON格式:[{"citta":"XXXX","via":"XXX","telefono":"1111-11111","provincia":"XX","clienteDesc":"Prova","clienteCode":"XXXXX"}],我使用此代码为jqGrid的:$("#clienti-navgrid").jqGrid({//data: c//
我有一个函数(在Java小服务程序)返回该JSON格式:
[{"citta":"XXXX","via":"XXX","telefono":"1111-11111","provincia":"XX","clienteDesc":"Prova","clienteCode":"XXXXX"}]
,我使用此代码为jqGrid的:
$("#clienti-navgrid").jqGrid({
//data: c
//datatype: "local"
datatype: "json",
url: '/project/loadnotespese.do',
colNames:['Codice Cliente','Descrizone Cliente','Via','Città','Provincia','Telefono'],
colModel:[
{name:'clienteCode', index:'clienteCode', width:'10', sortable:false},
{name:'clienteDesc', index:'clienteDesc', width:'20', sortable:false},
{name:'via', index:'via', width:'30', sortable:false},
{name:'citta', index:'citta', width:'20', sortable:false},
{name:'provincia', index:'provincia', width:'10', sortable:false},
{name:'telefono', index:'telefono', width:'10', sortable:false}
],
rowNum:500,
autowidth:true,
height:'auto',
recordtext:"Ordini trovati {2}",
emptyrecords:"Nessun risultato",
viewrecords: true,
caption: 'Tabella Clienti',
localReader : {
//
repeatitems: false,
}
});//jqGrid
,如果我把
var c = [{"citta":"XXXX","via":"XXX","telefono":"1111-11111","provincia":"XX","clienteDesc":"Prova","clienteCode":"XXXXX"}]
and
data: c, datatype: "local",
工作,但如果我从网址:'/project/loadnotespese.do',它不起作用。 有什么帮助吗?
+0
我忘了在'jsonReader'中提到'root'。请参阅** UPDATED **部分我的答案。 –
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