oracle判断是否是手机号码,oracle存储过程判断手机号码和固话
create or replace procedure get_Area_Phone(i_phoneNum in varchar2,--传入号码o_phoneFlag out varchar2,--返回手机号码1,固话2,其他0o_resultNum out varchar2)isiv_province varchar2(50);iv_phoneNum varchar2(50);iv_co...
create or replace procedure get_Area_Phone(i_phoneNum in varchar2,--传入号码
o_phoneFlag out varchar2,--返回手机号码1,固话2,其他0
o_resultNum out varchar2)
is
iv_province varchar2(50);
iv_phoneNum varchar2(50);
iv_count number;
iv_zipCode2 varchar2(50);
iv_zipCode varchar2(50);
v_strNum VARCHAR2(30);
v_400_phoneNum varchar2(50);
begin
iv_count := 0;
o_phoneFlag := '0';
--判断手机号码还是固话
if REGEXP_LIKE(i_phoneNum,'^1[3458]\d{9}$') then --判断手机号码
v_strNum := substr(i_phoneNum,0,7);
o_phoneFlag := '1';
select dpn.PROVINCE_NAME into iv_province from DIC_PHONE_NUM dpn WHERE dpn.MOBILE_NUMBER = v_strNum;
elsif REGEXP_LIKE(i_phoneNum,'^(010|02\d|0[3-9]\d{2})?\d{6,8}$') then --判断固话
iv_zipCode2 := substr(i_phoneNum,0,2);
o_phoneFlag := '2';
if (iv_zipCode2 = '01' or iv_zipCode2 = '02' or iv_zipCode2 = '85') then
if REGEXP_LIKE(substr(i_phoneNum,0,3),'^(010|852|853|02\d)$') then
iv_zipCode := substr(i_phoneNum,0,3);
end if;
else
if REGEXP_LIKE(substr(i_phoneNum,0,4),'^(0[3-9]\d{2})$') then
iv_zipCode := substr(i_phoneNum,0,4);
end if;
end if;
if iv_zipCode is not null then
select dpn.PROVINCE_NAME into iv_province from DIC_PHONE_NUM dpn WHERE dpn.area_code = iv_zipCode and rownum=1;
end if;
end if;
if iv_province is not null then select dpp.phone_num into o_resultNum from dic_phone_province dpp where dpp.province=iv_province; end if; exception --如果查不到对应的归属地返回 公用号码 when no_data_found then o_resultNum := '020'; end;
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