异步函数中的我的await语句是对jQuery的$.post()方法的调用,该方法返回一个有效的promise,但是我在TypeScript中遇到了这个错误：

Type of ‘await’ operand must either be a valid promise or must not contain a callable ‘then’ member.

我的功能是这个(示例简化).代码有效且有效,但我在TS控制台中收到错误.

async function doAsyncPost() {

const postUrl = 'some/url/';

const postData = {name: 'foo',value: 'bar'};

let postResult;

let upateResult;

function Failed(message: string,body?: string) {

console.log('error: ',message,' body: ',body);

}

function promiseFunc() {

return new Promise( resolve => {

// ... do something else....

resolve();

});

};

function finish() {

// ... do something at the end...

}

try {

// The error is on the $.post()

postResult = await $.post(postUrl,$.param(postData));

if (postResult.success !== 'true') {

return Failed('Error as occoured','Description.....');

}

await promiseFunc();

return finish();

} catch (e) {

await Failed('Error as occoured','Description.....');

}

}

我猜TS有$.post()的问题,因为你可以调用.then(),但是如何解决这个问题呢？此外,在更新2.4.2之前,我没有此错误.